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If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.
Note: If the number is a multiple of both 3 and 5, only count it once.
Solution:
public class Solution {
public int solution(int number) {
int sum = 0;
for (int i = 1; i < number; i++) {
if (i % 3 == 0 || i % 5 == 0) {
sum += i;
}
}
return sum;
}
}
Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.
Note: If the number is a multiple of both 3 and 5, only count it once.
Solution:
public class Solution {
public int solution(int number) {
int sum = 0;
for (int i = 1; i < number; i++) {
if (i % 3 == 0 || i % 5 == 0) {
sum += i;
}
}
return sum;
}
}